Haskell let in/where and if indentation -


i have function:

issimplenumber :: int -> bool issimplenumber x = let derivelist = map (\y -> (x `mod` y)) [1 .. x]                        filterlength = length ( filter (\z -> z == 0) derivelist                        ....

after filterlength want check how filterlength, try:

issimplenumber :: int -> bool issimplenumber x = let derivelist = map (\y -> (x `mod` y)) [1 .. x]                        filterlength = length ( filter (\z -> z == 0) derivelist                        in if filterlength == 2                           true

i error:

    parse error (possibly incorrect indentation) failed, modules loaded: none.

how can put indentation correctly if , in?

thank you.

this compile:

issimplenumber :: int -> bool issimplenumber x = let derivelist = map (\y -> (x `mod` y)) [1 .. x]                        filterlength = length ( filter (\z -> z == 0) derivelist )                    in filterlength == 2  main = print $ issimplenumber 5

there missing closing ")" after "derivelist". don't need if-then-true expression, also.


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