sql - stored procedure parameters -


how can pass these 2 value combination separated and/ parameter value stored procedure:

"8033301552*" or "08033301552*" 

or

"taiwo*" , "ayedun*" 

i mean need create string , pass parameter?

officially not supported.

a workaround can found at

http://groups.google.com/group/microsoft.public.sqlserver.reportingsvcs/browse_thread/thread/a5e0fdb24323aa13/e0fcc4c2d38883ec%23e0fcc4c2d38883ec?pli=1

what doesn't work has nothing rs has stored procedures in sql server. cannot following in stored procedure. let's have parameter called @myparams can map parameter multi-value parameter if in stored procedure try this: select * sometable somefield in (@myparams) won't work. try it. create stored procedure , try pass multi-value parameter stored procedure. won't work. can have string parameter passed multivalue parameter , change string table. technique told me sql server mvp, erland sommarskog example have done inner join charlist_to_table(@sto,default)f on b.sto = f.str note not issue rs, strictly stored procedure issue. here function:

create function charlist_to_table                      (@list      ntext,                       @delimiter nchar(1) = n',')           returns @tbl table (listpos int identity(1, 1) not null,                               str     varchar(4000),                               nstr    nvarchar(2000))     begin        declare @pos      int,                @textpos  int,                @chunklen smallint,                @tmpstr   nvarchar(4000),                @leftover nvarchar(4000),                @tmpval   nvarchar(4000)        set @textpos = 1        set @leftover = ''        while @textpos <= datalength(@list) / 2        begin           set @chunklen = 4000 - datalength(@leftover) / 2           set @tmpstr = @leftover + substring(@list, @textpos, @chunklen)           set @textpos = @textpos + @chunklen           set @pos = charindex(@delimiter, @tmpstr)           while @pos > 0           begin              set @tmpval = ltrim(rtrim(left(@tmpstr, @pos - 1)))              insert @tbl (str, nstr) values(@tmpval, @tmpval)              set @tmpstr = substring(@tmpstr, @pos + 1, len(@tmpstr))              set @pos = charindex(@delimiter, @tmpstr)           end           set @leftover = @tmpstr        end        insert @tbl(str, nstr) values (ltrim(rtrim(@leftover)),  ltrim(rtrim(@leftover)))     return     end  go  

-- bruce loehle-conger mvp sql server reporting services "roland müller" wrote in message


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