desperately simple python decimal -


hi need please. want calculate float numbers format xxxxx.yyyyyyyyyyyyyyy. have learned should use decimal instead of float tried lot, , searched lot still have following simple problem:

    getcontext().prec = 14     = decimal(str('12.737791301'))     b = decimal(str('12.737791839'))     c = decimal((b - a)) # substract want here      print a, b, c  12.737791301 12.737791839 5.38e-7

i want c displayed 0.000000538

thanks help!

ps. normalize() did not work

the real solution format(), available in python 2.6 , 3.1.

format(c,"f") convert decimal float repr-style output. part of new style formatting in python.

other worse ideas solutions below:

this can accomplished format string, if decimal values floats. print "%0.9f" % c produce '0.000000538'

the python library reference can tell more.

to around problem of needing know right number of decimal places, print out @ limit of float precision condition in case decimal smaller:

out = "%.16f" % c if c >= 1e-16 else "0.0" print out.rstrip('0')

with second line dealing trailing 0s.


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