Display line starting with word in a file Python regex -


i have file "abc.txt" following contents..

emboss_001       601 fedsesrrdslfvphrpgerrnsngtttetevrkrrlssyqismemleds    650                           :...::.||...||....|..|.|....    |..:.|.|.|..: emboss_002         1 -----npsltvtvpiavgesdfenlnteefsse----seleeskeklnat     41  emboss_001       651 sgrqrs-msiasiltntmeele-esrqkcppcw-------yrfanvfliw    691                      |..:.| :.:|........|:| |...|...|:       :.|..|.... emboss_002        42 sssegstvdvappregeqaeiepeedlkpeacftegcikkfpfcqvstee     91

i want create 3 strings.. first string "a" should have characters thats written after emboss_001 (of both lines) ie

a="fedsesrrdslfvphrpgerrnsngtttetevrkrrlssyqismemledssgrqrs-msiasiltntmeele-esrqkcppcw-------yrfanvfliw"

second string should have written after emboss_002 (of both lines) minus numbers ie 

b="-----npsltvtvpiavgesdfenlnteefsse----seleeskeklnatsssegstvdvappregeqaeiepeedlkpeacftegcikkfpfcqvstee"

and third string c should whatever between emboss_1 , emboss_2 (alphanumeric characters or -) in both lines 

c="     :...::.||...||....|..|.|....    |..:.|.|.|..|..:.| :.:|........|:| |...|...|:       :.|..|...."

the original spaces @ start, end(if any) , @ middle of c should intact. in case 5 spaces @ start since c starts "f" of , "-" of b

thanks

no 1 going write code you. however, tell you'll want use regular expressions/regex (the "re" module in python). read http://docs.python.org/library/re.html , http://docs.python.org/howto/regex.html


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