php - ajax script doesn't work in IE -


i have problem ajax script in ie, because doesn't work, works in ff , chrome in ie doesn't work! there 2 drop down boxes , according have selected in first 1 second dropdown box show values selected city.

    <select class="selectdest" name="prej" onchange="getstate(this.value)">         <option></option>         '.funksionet::all_directions().'     </select>

this second dropdown box:

    <div id="statediv"><select class="selectdest" name="deri">         <option></option>     </select></div>

this ajax function: 

<script language="javascript" type="text/javascript"> function getxmlhttp() { //function return xml http object         var xmlhttp=false;           try{             xmlhttp=new xmlhttprequest();         }         catch(e)    {                    try{                             xmlhttp= new activexobject("microsoft.xmlhttp");             }             catch(e){                 try{                 xmlhttp = new activexobject("msxml2.xmlhttp");                 }                 catch(e1){                     xmlhttp=false;                 }             }         }          return xmlhttp;     }      function getstate(countryid) {                var strurl="findstate.php?country="+countryid;         var req = getxmlhttp();          if (req) {              req.onreadystatechange = function() {                 if (req.readystate == 4) {                     // if "ok"                     if (req.status == 200) {                                                 document.getelementbyid(\'statediv\').innerhtml=req.responsetext;                                            } else {                         alert("there problem while using xmlhttp:\n" + req.statustext);                     }                 }                            }                        req.open("get", strurl, true);             req.send(null);         }            } </script>

this findstate.php file:

<?php  require_once 'includes/constants.php'; $country = $_get['country']; $link = mysql_connect(db_server, db_user, db_password); //changet configuration in required if (!$link) {     die('could not connect: ' . mysql_error("1")); } mysql_select_db(db_name); $query="select * costs prej = '$country';"; $result=mysql_query($query) or die("2"); ?> <select class="selectdest" name="deri">  <option></option>   <?php while($row = mysql_fetch_array($result)) {      print'<option>'.$row['deri'].'</option>';    }  ?> </select>

i need make work, appreciate if going me on this. because not javascript! if there no way can cross-browser know , wont make way.

$country = $_get['country']; $query="select * costs prej = '$country';";

i know, offtopic, not


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