c++ - Can we declare a function with the same signature but different return type in the base class? -


the question may silly ,but want ask.. there way can declare method in class same signature different return type (like int fun(int) , float fun(int) ) , during object creation can dynamically decide function executed! have got compilation error...is there other way achieve logic may using templates...

you can take return value template.

template<typename t> t fun(int); template<> float fun<float>(int); template<> int fun<int>(int);

can decide dynamically @ run-time call? no.


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