sorting - How to sort IP addresses stored in dictionary in Python? -

i have piece of code looks this:

ipcount = defaultdict(int)  logline in loglines:     date, serverip, clientip = logline.split(" ")     ipcount[clientip] += 1  clientip, hitcount in sorted(ipcount.items), key=operator.itemgetter(0)):     print(clientip) 

and kind of sorts ip's, this:

192.168.102.105 192.168.204.111 192.168.99.11 

which not enough since not recognize 99 smaller number 102 or 204. output this:

192.168.99.11 192.168.102.105 192.168.204.111 

i found this, not sure how implement in code, or if possible since use dictionary. options here? thank you..

you can use custom key function return sortable representation of strings:

def split_ip(ip):     """split ip address given string 4-tuple of integers."""     return tuple(int(part) part in ip.split('.'))  def my_key(item):     return split_ip(item[0])  items = sorted(ipcount.items(), key=my_key) 

the split_ip() function takes ip address string '192.168.102.105' , turns tuple of integers (192, 168, 102, 105). python has built-in support sort tuples lexicographically.

update: can done easier using inet_aton() function in socket module:

import socket items = sorted(ipcount.items(), key=lambda item: socket.inet_aton(item[0]))