php - Opening submenu depending on the selected page -


i designing vertical drop menu (with submenus), here's how looks:

click here see screenshot

on left, no menu item selected. on middle , on right there sub-menus opened (and selected page in blue). 1 sub-menu can opened @ once (one opens => other closes). contents of menu not dynamic.

the big problem when opened new page, sub-menu of selected page had opened.

so decided pages links index.php?p=my_selected_page , in file menu.php built array:

$menu = array(     'présentation' => array(         'accueil' => 'accueil',         'inscription' => 'inscrivez-vous'     ),     'nos actions' => array(         'mediation-familiale' => 'médiation familiale',         'droit-de-visite' => 'droit de visite accompagnée',         'accompagnement-familial' => 'accompagnement familial'     )     // [...] );

then page $_get ['p']. through array , writes menu html match. if $_get['p'] 1 of key sub-array, display sub-menu css class menu open. (and link selected default).

while solution works, system allows me store links index.php?p=my_selected_page.

i wish put other links, forum.php (and include menu.php in forum.php), etc..

if have ideas make possible, grateful.

(i french. sorry spelling mistakes.)

you use $_server["script_name"] ask name of script file, , verification information, not sending variable via get. :)

e.g.

<?php  $script_file = $_server["script_name"]; $no_slashes = explode('/', $script_file); $script_file = $no_slashes[count($no_slashes) - 1];   echo $script_file;  ?>

at point, have filename stored in $script_file, , match array's keys.

hope helps.


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