bitflags - How to format flags in c? -


assume there flag definitions such as:

shf_write     0x1 shf_alloc     0x2 shf_execinstr 0x4 shf_maskproc  0xf0000000

given flag, need output shf_write|shf_alloc if bits 0x1 , 0x2 on.

how trick in c?

just create character buffer enough space hold possible combinations of strings , add appropriate strings each applicable bit set. (or ditch buffer , write straight stdout, choice) here's naive implementation of how such thing:

void print_flags(int flag) { #define buflen (9+9+13+12+3+1)                   /* text, pipes , null terminator*/ #define pairlen 4 static struct { int value; const char *string; } pair[] = {     { shf_write,     "shf_write" },     { shf_alloc,     "shf_alloc" },     { shf_execinstr, "shf_execinstr" },     { shf_maskproc,  "shf_maskproc" }, };      char buf[buflen];  /* declare buffer */     char *write = buf;    /* , "write" pointer */     int i;     (i = 0; < pairlen; i++)     {         if ((flag & pair[i].value) == pair[i].value) /* if flag set... */         {             size_t written = write - buf;             write += _snprintf(write, buflen-written, "%s%s",                 written > 0 ? "|" : "",                 pair[i].string); /* write buffer */         }     }     if (write != buf) /* if of flags set... */     {         *write = '\0'; /* null terminate (just in case) */         printf("(%s)", buf); /* print out buffer */     } #undef pairlen #undef buflen }

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