Lua pattern: how to fetch the required string -
i have string mentioned below, data coming me in excel file. rows proper data , these proper data rows able fetch need using lua pattern. below proper data row
2011/02 arrtc aauumco zzitnwmobile communications center arrtc-aauum-tbt-2011-02 0.00 aauum_arrtc_0211_tbt 18.03 18.03 eur 1.14977 20.73 20.73
and using below pattern , working fine.
rpattern = "(%d%d%d%d%/%d%d)%s*(%w%w%w[%w%d][%w%d])%s*(%w%w%w[%w%d][%w%d]).-[%u%d%-%s]-([%d%.%,]+)%s*([%u%d_%-]-)%s*([%d%.%,]+)%s*([%d%.%,]+)%s*(%u%u%u)%s*(%d+%.%d*)%s*(.-)\n"
now rows coming html tags, means data inside html tags. trick need fetch required string within html tags. bugged row
2011/02 arrtc aauumco zzitnwmobile communications center arrtc-aauum-tbt-2011-02 0.00 <a href="/cgi-bin/recon_detail?rectent=aauum&benificary=arrtc&period=2011/02&svctype=voice">aauum_arrtc_0211_tbt</a> 18.03 18.03 eur 1.14977 20.73 20.73
now above row want fetch aauum_arrtc_0211_tbt
i trying trying , trying unable it. can me fix above patternd?
thanks
try print(str:match(">(.-)<"))
.
Comments
Post a Comment