python - list with xyz values to dictionary -

i have list:

list = [ '1', '1,'1', '-1','1','-1' ] 

and need convert dictionary of dictionaries. first 3 values in x y z , second set 3 values x y z. result should be:

d = { 0:{x:1,y:1,z:1}, 1:{x:-1,y:1,z:-1}} 

my attempt:

mylist=[1,1,1,-1,1,-1] count = 1 keycount = 0 l = {'x':' ','y':' ', 'z':' '} t = {} 1 in mylist:         if count == 1:                 l['x'] = 1                 print l         if count == 2:                 l['y'] = 1                 print l         if count == 3:                 l['z'] = 1                 print l                 count = 0                 t[keycount] = l                 l = {}                 keycount += 1         count = count + 1 print t 

but in result switches of keys of dictionary? have better solution?

a bit complicated one:

l = [ '1', '1', '1', '-1', '1', '-1' ]  dicts = [dict(zip(['x', 'y', 'z'], l[i:i+3])) in range(0, len(l), 3)] result = dict(enumerate(dicts))  print result #prints {0: {'y': '1', 'x': '1', 'z': '1'}, 1: {'y': '1', 'x': '-1', 'z': '-1'}}