sql - MySQL Order year field by closest match -


i'm trying order dates listed in particular order closest specified date:

id  year --------- 1   2010 2   2011 3   1992 4   1996 5   1987 6   1988

the result should (if specify 1992 year order by):

id  year ---------  3   1992 4   1996 <4 away 5   1987 <5 away 6   1988 <6 away 1   2010 <8 away 2   2011 <9 away

i want returns dates, relevant (closest) first in list.

sorry have revised question make more clear i'm trying achieve.

this should solve problem.

select * `table` order abs(1992-`year`) asc

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